Flattening the sub-lists












2












$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


Into



{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}


I know I can do 



Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


I am wondering whether there are some dedicated functions for such sub-list flattening?






list-manipulation







share|improve this question











$endgroup$








  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    5 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago
















2












$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


Into



{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}


I know I can do 



Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


I am wondering whether there are some dedicated functions for such sub-list flattening?






list-manipulation







share|improve this question











$endgroup$








  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    5 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago














2












2








2





$begingroup$


Is there a way to flatten the sub-lists within a list?



Transform



{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


Into



{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}


I know I can do 



Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


I am wondering whether there are some dedicated functions for such sub-list flattening?






list-manipulation







share|improve this question











$endgroup$




Is there a way to flatten the sub-lists within a list?



Transform



{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


Into



{{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, x}, {9, x}, {10, x}}


I know I can do 



Flatten /@ {{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}


I am wondering whether there are some dedicated functions for such sub-list flattening?






list-manipulation




list-manipulation






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago









m0nhawk

2,92711532




2,92711532










asked 5 hours ago









bakerbaker

463




463








  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    5 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago














  • 3




    $begingroup$
    try Flatten[list,1]
    $endgroup$
    – J42161217
    5 hours ago










  • $begingroup$
    One can also consider using Join @@ yourlist.
    $endgroup$
    – Αλέξανδρος Ζεγγ
    3 hours ago








3




3




$begingroup$
try Flatten[list,1]
$endgroup$
– J42161217
5 hours ago




$begingroup$
try Flatten[list,1]
$endgroup$
– J42161217
5 hours ago












$begingroup$
One can also consider using Join @@ yourlist.
$endgroup$
– Αλέξανδρος Ζεγγ
3 hours ago




$begingroup$
One can also consider using Join @@ yourlist.
$endgroup$
– Αλέξανδρος Ζεγγ
3 hours ago










1 Answer
1






active

oldest

votes


















7












$begingroup$

You are doing redundant step with /@, Flatten can make this directly:



Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 

    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]

(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 

  x}, {9, x}, {10, x}} *)





share|improve this answer









$endgroup$














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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    You are doing redundant step with /@, Flatten can make this directly:



    Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 
    
    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]
    
(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 
    
  x}, {9, x}, {10, x}} *)





    share|improve this answer









    $endgroup$


















      7












      $begingroup$

      You are doing redundant step with /@, Flatten can make this directly:



      Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 
      
    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]
      
(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 
      
  x}, {9, x}, {10, x}} *)





      share|improve this answer









      $endgroup$
















        7












        7








        7





        $begingroup$

        You are doing redundant step with /@, Flatten can make this directly:



        Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 
        
    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]
        
(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 
        
  x}, {9, x}, {10, x}} *)





        share|improve this answer









        $endgroup$



        You are doing redundant step with /@, Flatten can make this directly:



        Flatten[{{{1, x}}, {{2, x}}, {{3, x}}, {{4, x}}, {{5, 
        
    x}}, {{6, x}}, {{7, x}}, {{8, x}}, {{9, x}}, {{10, x}}}, 1]
        
(* {{1, x}, {2, x}, {3, x}, {4, x}, {5, x}, {6, x}, {7, x}, {8, 
        
  x}, {9, x}, {10, x}} *)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 5 hours ago









        m0nhawkm0nhawk

        2,92711532




        2,92711532






























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