Why source (or dot command) doesn't require the file to be executable
From running help .
or help source
Execute commands from a file in the current shell.
Read and execute commands from FILENAME in the current shell. The
entries in $PATH are used to find the directory containing FILENAME.
From my point of view, it seems like the dot command (or the source
command) is simply running a shell script in the current shell context (instead of spawning another shell).
Question: why doesn't .
(or source
) requires the file to be executable like when you run a normal script?
shell-script shell
add a comment |
From running help .
or help source
Execute commands from a file in the current shell.
Read and execute commands from FILENAME in the current shell. The
entries in $PATH are used to find the directory containing FILENAME.
From my point of view, it seems like the dot command (or the source
command) is simply running a shell script in the current shell context (instead of spawning another shell).
Question: why doesn't .
(or source
) requires the file to be executable like when you run a normal script?
shell-script shell
1
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
This behavior is surprising to me because normally running a shell script as in./ script
requires the script to be executable.
– Tran Triet
11 hours ago
@UncleBilly So that you don't accidentally type. ~/.bash_history
instead of. ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336
– Joker_vD
9 hours ago
add a comment |
From running help .
or help source
Execute commands from a file in the current shell.
Read and execute commands from FILENAME in the current shell. The
entries in $PATH are used to find the directory containing FILENAME.
From my point of view, it seems like the dot command (or the source
command) is simply running a shell script in the current shell context (instead of spawning another shell).
Question: why doesn't .
(or source
) requires the file to be executable like when you run a normal script?
shell-script shell
From running help .
or help source
Execute commands from a file in the current shell.
Read and execute commands from FILENAME in the current shell. The
entries in $PATH are used to find the directory containing FILENAME.
From my point of view, it seems like the dot command (or the source
command) is simply running a shell script in the current shell context (instead of spawning another shell).
Question: why doesn't .
(or source
) requires the file to be executable like when you run a normal script?
shell-script shell
shell-script shell
asked 13 hours ago
Tran TrietTran Triet
1128
1128
1
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
This behavior is surprising to me because normally running a shell script as in./ script
requires the script to be executable.
– Tran Triet
11 hours ago
@UncleBilly So that you don't accidentally type. ~/.bash_history
instead of. ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336
– Joker_vD
9 hours ago
add a comment |
1
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
This behavior is surprising to me because normally running a shell script as in./ script
requires the script to be executable.
– Tran Triet
11 hours ago
@UncleBilly So that you don't accidentally type. ~/.bash_history
instead of. ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336
– Joker_vD
9 hours ago
1
1
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
This behavior is surprising to me because normally running a shell script as in
./ script
requires the script to be executable.– Tran Triet
11 hours ago
This behavior is surprising to me because normally running a shell script as in
./ script
requires the script to be executable.– Tran Triet
11 hours ago
@UncleBilly So that you don't accidentally type
. ~/.bash_history
instead of . ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336– Joker_vD
9 hours ago
@UncleBilly So that you don't accidentally type
. ~/.bash_history
instead of . ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336– Joker_vD
9 hours ago
add a comment |
2 Answers
2
active
oldest
votes
Lets say I have a shell script (my-script.sh
)starting with:
#!/bin/sh
If the script has execute permissions set then I can run the script with:
./my-script.sh
In this case you are ultimately asking the kernel to run my-script.sh
as a program, and the kernel (program loader) will check permissions first, and then use /bin/sh ./my-script.sh
to actually execute your script.
But the shell (/bin/sh
) does not care about execute permissions and doesn't check them. So if you call this ...
/bin/sh ./my-script.sh
... The kernel is never asked to run my-script.sh
as a program. The kernel (program loader) is only asked to run /bin/sh
. So the execute permissions will never me checked. That is, you don't need execute permission to run a script like this.
To answer your question:
The difference between you calling ./my-script.sh
and . ./my-script.sh
inside another script is exactly the same. In the first, you are asking the kernel to run it as a program, in the second, you are asking your current shell to read commands from the script and the shell doesn't need (or care about) execute permissions to do this.
Further reading:
Running scripts as programs is surprising behaviour when you think about it. They are not written in machine code. I would read up on why this works; start with reading up on the shebang (#!
) https://en.wikipedia.org/wiki/Shebang_(Unix)
Running scripts with the dot notation is necessary to share variables. All other mechanisms for running start a new shell "context", meaning that any variables set in the called script will not be passed back to the calling script. Bash documentation is a little lite, but it's here: https://www.gnu.org/software/bash/manual/html_node/Bourne-Shell-Builtins.html
1
When sourced, then$0
is your bash. If the script is executed, then$0
is./my-script.sh
.
– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run/bin/bash non-executable-file
.
– Tran Triet
12 hours ago
1
@Philip Couling When sourced withsource my-script.sh
or. my-script.sh
.
– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
@TranTriet Also be aware that running a script withbash ./my-script.sh
or. ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.
– Philip Couling
12 hours ago
|
show 2 more comments
When you say source script.sh
or . script.sh
you are never executing the script. What you are running is a shell command source
which does something. This "something" includes reading from script.sh and executing what-has-been-read. Your script needs to be readable for this. No need for executability.
The behaviour is similar to running bash non-executable-script.sh
or python non-executable-script.py
etc.
New contributor
add a comment |
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2 Answers
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active
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2 Answers
2
active
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votes
Lets say I have a shell script (my-script.sh
)starting with:
#!/bin/sh
If the script has execute permissions set then I can run the script with:
./my-script.sh
In this case you are ultimately asking the kernel to run my-script.sh
as a program, and the kernel (program loader) will check permissions first, and then use /bin/sh ./my-script.sh
to actually execute your script.
But the shell (/bin/sh
) does not care about execute permissions and doesn't check them. So if you call this ...
/bin/sh ./my-script.sh
... The kernel is never asked to run my-script.sh
as a program. The kernel (program loader) is only asked to run /bin/sh
. So the execute permissions will never me checked. That is, you don't need execute permission to run a script like this.
To answer your question:
The difference between you calling ./my-script.sh
and . ./my-script.sh
inside another script is exactly the same. In the first, you are asking the kernel to run it as a program, in the second, you are asking your current shell to read commands from the script and the shell doesn't need (or care about) execute permissions to do this.
Further reading:
Running scripts as programs is surprising behaviour when you think about it. They are not written in machine code. I would read up on why this works; start with reading up on the shebang (#!
) https://en.wikipedia.org/wiki/Shebang_(Unix)
Running scripts with the dot notation is necessary to share variables. All other mechanisms for running start a new shell "context", meaning that any variables set in the called script will not be passed back to the calling script. Bash documentation is a little lite, but it's here: https://www.gnu.org/software/bash/manual/html_node/Bourne-Shell-Builtins.html
1
When sourced, then$0
is your bash. If the script is executed, then$0
is./my-script.sh
.
– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run/bin/bash non-executable-file
.
– Tran Triet
12 hours ago
1
@Philip Couling When sourced withsource my-script.sh
or. my-script.sh
.
– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
@TranTriet Also be aware that running a script withbash ./my-script.sh
or. ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.
– Philip Couling
12 hours ago
|
show 2 more comments
Lets say I have a shell script (my-script.sh
)starting with:
#!/bin/sh
If the script has execute permissions set then I can run the script with:
./my-script.sh
In this case you are ultimately asking the kernel to run my-script.sh
as a program, and the kernel (program loader) will check permissions first, and then use /bin/sh ./my-script.sh
to actually execute your script.
But the shell (/bin/sh
) does not care about execute permissions and doesn't check them. So if you call this ...
/bin/sh ./my-script.sh
... The kernel is never asked to run my-script.sh
as a program. The kernel (program loader) is only asked to run /bin/sh
. So the execute permissions will never me checked. That is, you don't need execute permission to run a script like this.
To answer your question:
The difference between you calling ./my-script.sh
and . ./my-script.sh
inside another script is exactly the same. In the first, you are asking the kernel to run it as a program, in the second, you are asking your current shell to read commands from the script and the shell doesn't need (or care about) execute permissions to do this.
Further reading:
Running scripts as programs is surprising behaviour when you think about it. They are not written in machine code. I would read up on why this works; start with reading up on the shebang (#!
) https://en.wikipedia.org/wiki/Shebang_(Unix)
Running scripts with the dot notation is necessary to share variables. All other mechanisms for running start a new shell "context", meaning that any variables set in the called script will not be passed back to the calling script. Bash documentation is a little lite, but it's here: https://www.gnu.org/software/bash/manual/html_node/Bourne-Shell-Builtins.html
1
When sourced, then$0
is your bash. If the script is executed, then$0
is./my-script.sh
.
– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run/bin/bash non-executable-file
.
– Tran Triet
12 hours ago
1
@Philip Couling When sourced withsource my-script.sh
or. my-script.sh
.
– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
@TranTriet Also be aware that running a script withbash ./my-script.sh
or. ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.
– Philip Couling
12 hours ago
|
show 2 more comments
Lets say I have a shell script (my-script.sh
)starting with:
#!/bin/sh
If the script has execute permissions set then I can run the script with:
./my-script.sh
In this case you are ultimately asking the kernel to run my-script.sh
as a program, and the kernel (program loader) will check permissions first, and then use /bin/sh ./my-script.sh
to actually execute your script.
But the shell (/bin/sh
) does not care about execute permissions and doesn't check them. So if you call this ...
/bin/sh ./my-script.sh
... The kernel is never asked to run my-script.sh
as a program. The kernel (program loader) is only asked to run /bin/sh
. So the execute permissions will never me checked. That is, you don't need execute permission to run a script like this.
To answer your question:
The difference between you calling ./my-script.sh
and . ./my-script.sh
inside another script is exactly the same. In the first, you are asking the kernel to run it as a program, in the second, you are asking your current shell to read commands from the script and the shell doesn't need (or care about) execute permissions to do this.
Further reading:
Running scripts as programs is surprising behaviour when you think about it. They are not written in machine code. I would read up on why this works; start with reading up on the shebang (#!
) https://en.wikipedia.org/wiki/Shebang_(Unix)
Running scripts with the dot notation is necessary to share variables. All other mechanisms for running start a new shell "context", meaning that any variables set in the called script will not be passed back to the calling script. Bash documentation is a little lite, but it's here: https://www.gnu.org/software/bash/manual/html_node/Bourne-Shell-Builtins.html
Lets say I have a shell script (my-script.sh
)starting with:
#!/bin/sh
If the script has execute permissions set then I can run the script with:
./my-script.sh
In this case you are ultimately asking the kernel to run my-script.sh
as a program, and the kernel (program loader) will check permissions first, and then use /bin/sh ./my-script.sh
to actually execute your script.
But the shell (/bin/sh
) does not care about execute permissions and doesn't check them. So if you call this ...
/bin/sh ./my-script.sh
... The kernel is never asked to run my-script.sh
as a program. The kernel (program loader) is only asked to run /bin/sh
. So the execute permissions will never me checked. That is, you don't need execute permission to run a script like this.
To answer your question:
The difference between you calling ./my-script.sh
and . ./my-script.sh
inside another script is exactly the same. In the first, you are asking the kernel to run it as a program, in the second, you are asking your current shell to read commands from the script and the shell doesn't need (or care about) execute permissions to do this.
Further reading:
Running scripts as programs is surprising behaviour when you think about it. They are not written in machine code. I would read up on why this works; start with reading up on the shebang (#!
) https://en.wikipedia.org/wiki/Shebang_(Unix)
Running scripts with the dot notation is necessary to share variables. All other mechanisms for running start a new shell "context", meaning that any variables set in the called script will not be passed back to the calling script. Bash documentation is a little lite, but it's here: https://www.gnu.org/software/bash/manual/html_node/Bourne-Shell-Builtins.html
edited 11 hours ago
answered 13 hours ago
Philip CoulingPhilip Couling
1,076817
1,076817
1
When sourced, then$0
is your bash. If the script is executed, then$0
is./my-script.sh
.
– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run/bin/bash non-executable-file
.
– Tran Triet
12 hours ago
1
@Philip Couling When sourced withsource my-script.sh
or. my-script.sh
.
– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
@TranTriet Also be aware that running a script withbash ./my-script.sh
or. ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.
– Philip Couling
12 hours ago
|
show 2 more comments
1
When sourced, then$0
is your bash. If the script is executed, then$0
is./my-script.sh
.
– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run/bin/bash non-executable-file
.
– Tran Triet
12 hours ago
1
@Philip Couling When sourced withsource my-script.sh
or. my-script.sh
.
– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
@TranTriet Also be aware that running a script withbash ./my-script.sh
or. ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.
– Philip Couling
12 hours ago
1
1
When sourced, then
$0
is your bash. If the script is executed, then $0
is ./my-script.sh
.– Freddy
12 hours ago
When sourced, then
$0
is your bash. If the script is executed, then $0
is ./my-script.sh
.– Freddy
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run
/bin/bash non-executable-file
.– Tran Triet
12 hours ago
Thank you very much. Your answer surprises me by the fact that I could run
/bin/bash non-executable-file
.– Tran Triet
12 hours ago
1
1
@Philip Couling When sourced with
source my-script.sh
or . my-script.sh
.– Freddy
12 hours ago
@Philip Couling When sourced with
source my-script.sh
or . my-script.sh
.– Freddy
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
@Freddy much clearer. Thanks.
– Philip Couling
12 hours ago
2
2
@TranTriet Also be aware that running a script with
bash ./my-script.sh
or . ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.– Philip Couling
12 hours ago
@TranTriet Also be aware that running a script with
bash ./my-script.sh
or . ./my-script.sh
, the shebang (#!/bin/sh
) will be completely ignored. This can be a problem when crossing between different shells.– Philip Couling
12 hours ago
|
show 2 more comments
When you say source script.sh
or . script.sh
you are never executing the script. What you are running is a shell command source
which does something. This "something" includes reading from script.sh and executing what-has-been-read. Your script needs to be readable for this. No need for executability.
The behaviour is similar to running bash non-executable-script.sh
or python non-executable-script.py
etc.
New contributor
add a comment |
When you say source script.sh
or . script.sh
you are never executing the script. What you are running is a shell command source
which does something. This "something" includes reading from script.sh and executing what-has-been-read. Your script needs to be readable for this. No need for executability.
The behaviour is similar to running bash non-executable-script.sh
or python non-executable-script.py
etc.
New contributor
add a comment |
When you say source script.sh
or . script.sh
you are never executing the script. What you are running is a shell command source
which does something. This "something" includes reading from script.sh and executing what-has-been-read. Your script needs to be readable for this. No need for executability.
The behaviour is similar to running bash non-executable-script.sh
or python non-executable-script.py
etc.
New contributor
When you say source script.sh
or . script.sh
you are never executing the script. What you are running is a shell command source
which does something. This "something" includes reading from script.sh and executing what-has-been-read. Your script needs to be readable for this. No need for executability.
The behaviour is similar to running bash non-executable-script.sh
or python non-executable-script.py
etc.
New contributor
New contributor
answered 8 hours ago
MetMet
1212
1212
New contributor
New contributor
add a comment |
add a comment |
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1
why should it? when making a question like this, it would help if you explain why you find the behavior surprising. Otherwise, the same could be asked: why aren't C source file executables? etc.
– Uncle Billy
11 hours ago
This behavior is surprising to me because normally running a shell script as in
./ script
requires the script to be executable.– Tran Triet
11 hours ago
@UncleBilly So that you don't accidentally type
. ~/.bash_history
instead of. ~/.bash_profile
, for example? twitter.com/munificentbob/status/1091220194020622336– Joker_vD
9 hours ago