Why doesn't using two cd commands in bash script execute the second command?
I have written a bash script which create series of directories, and clones a project to selected directories.
For that I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory and execute the command.
Instead, it stops after cd and cloning in theproject2
directory. Why it doesn't call the cd_project1
function in following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
|
show 3 more comments
I have written a bash script which create series of directories, and clones a project to selected directories.
For that I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory and execute the command.
Instead, it stops after cd and cloning in theproject2
directory. Why it doesn't call the cd_project1
function in following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
1
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
1
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
2
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
5 hours ago
|
show 3 more comments
I have written a bash script which create series of directories, and clones a project to selected directories.
For that I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory and execute the command.
Instead, it stops after cd and cloning in theproject2
directory. Why it doesn't call the cd_project1
function in following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
New contributor
I have written a bash script which create series of directories, and clones a project to selected directories.
For that I need to cd
to each directory (project 1
and project 2
), but the script doesn't cd
to the second directory and execute the command.
Instead, it stops after cd and cloning in theproject2
directory. Why it doesn't call the cd_project1
function in following code?
#!/bin/bash
#Get the current user name
function my_user_name() {
current_user=$USER
echo " Current user is $current_user"
}
#Creating useful directories
function create_useful_directories() {
if [[ ! -d "$scratch" ]]; then
echo "creating relevant directory"
mkdir -p /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2
else
echo "scratch directory already exists"
:
fi
}
#Going to project2 and cloning
function cd_project2() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/project2 &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Going to project1 directory and cloning
function cd_project1() {
cd /home/"$current_user"/Downloads/scratch/"$current_user"/project1/ &&
git clone https://username@bitbucket.org/teamsinspace/documentation-tests.git
exec bash
}
#Running the functions
function main() {
my_user_name
create_useful_directories
cd_project2
cd_project1
}
main
Terminal output:
~/Downloads$. ./bash_install_script.sh
Current user is mihi
creating relevant directory
Cloning into 'documentation-tests'...
remote: Counting objects: 125, done.
remote: Compressing objects: 100% (115/115), done.
remote: Total 125 (delta 59), reused 0 (delta 0)
Receiving objects: 100% (125/125), 33.61 KiB | 362.00 KiB/s, done.
Resolving deltas: 100% (59/59), done.
~/Downloads/scratch/mihi/project1/project2$
bash scripts cd-command
bash scripts cd-command
New contributor
New contributor
edited 10 mins ago
Olorin
2,657924
2,657924
New contributor
asked 7 hours ago
JennyJenny
313
313
New contributor
New contributor
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
1
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
1
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
2
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
5 hours ago
|
show 3 more comments
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
1
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
1
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
2
I'm curious what you intended for theexec bash
to do.
– Dennis Williamson
5 hours ago
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
1
1
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
1
1
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
2
2
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
5 hours ago
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
5 hours ago
|
show 3 more comments
2 Answers
2
active
oldest
votes
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
4 hours ago
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
Thanks! It works.
– Jenny
6 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
4 hours ago
add a comment |
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
4 hours ago
add a comment |
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
The culprits are your exec bash
statements in some of your functions.
The exec
statement is a bit weird and not easily understood in the first place.
It means: execute the following command instead of the currently running
command/shell/script from here on. That is: it replaces the current shell
script (in your case) with an instance of bash
and it never returns.
You can try this out with a shell and issue
exec sleep 5
This will replace your current shell (the bash
) with the command sleep 5
and when that command returns (after 5 seconds) your window will close because
the shell has been replaced with sleep 5
.
Same with your script: If you put exec something
into your script, the script
gets replaced with something
and when that something
stops execution, the
whole script stops.
Simply dropping the exec bash
statements should do.
answered 7 hours ago
PerlDuckPerlDuck
7,06611536
7,06611536
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
4 hours ago
add a comment |
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has anexec
statement with the same behaviour and if you put some statements after anexec
statement (likeexec something; print "This won't run";
) then Perl will warn you that theprint
statement will never get executed.
– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t useset -e
). I have seen Code likecd tmp; rm -rf *
fail horrible
– eckes
4 hours ago
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
Oh thanks! it worked. Never thought it would be that simpler. Jenny :)
– Jenny
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has an
exec
statement with the same behaviour and if you put some statements after an exec
statement (like exec something; print "This won't run";
) then Perl will warn you that the print
statement will never get executed.– PerlDuck
6 hours ago
@Jenny Nice to hear. Anecdote: The Perl language also has an
exec
statement with the same behaviour and if you put some statements after an exec
statement (like exec something; print "This won't run";
) then Perl will warn you that the print
statement will never get executed.– PerlDuck
6 hours ago
BTW congrats on using && after cd, (if you don’t use
set -e
). I have seen Code like cd tmp; rm -rf *
fail horrible– eckes
4 hours ago
BTW congrats on using && after cd, (if you don’t use
set -e
). I have seen Code like cd tmp; rm -rf *
fail horrible– eckes
4 hours ago
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
Thanks! It works.
– Jenny
6 hours ago
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
Thanks! It works.
– Jenny
6 hours ago
add a comment |
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
From help exec
:
exec: exec [-cl] [-a name] [command [arguments ...]] [redirection ...]
Replace the shell with the given command.
Execute COMMAND, replacing this shell with the specified program.
ARGUMENTS become the arguments to COMMAND. If COMMAND is not specified,
any redirections take effect in the current shell.
The key word here is replace - if you exec bash
from inside a script, no further script execution can occur.
answered 7 hours ago
steeldriversteeldriver
69.2k11114185
69.2k11114185
Thanks! It works.
– Jenny
6 hours ago
add a comment |
Thanks! It works.
– Jenny
6 hours ago
Thanks! It works.
– Jenny
6 hours ago
Thanks! It works.
– Jenny
6 hours ago
add a comment |
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
Jenny is a new contributor. Be nice, and check out our Code of Conduct.
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Consider accepting one of the answers. If more than one answer is a solution to a question - accept the best one and up-vote another.
– LeonidMew
6 hours ago
Hi LeonidMew. Sorry I have no idea how to accept the answers. Both answers are equally good though.
– Jenny
6 hours ago
1
@Jenny, don't feel rushed. Read What should I do when someone answers my question? instead and act accordingly when you are satisfied. Just take your time, there is no reason to hurry. It's perfectly OK if you decide in a day or in a week or in whatever time it takes.
– PerlDuck
6 hours ago
1
@LeonidMew it's barely been 45 minutes since the question was asked, waiting longer is A-OK, a better answer might even come along (like PerlDuck's comment says, it just popped up while I was typing)
– Xen2050
6 hours ago
2
I'm curious what you intended for the
exec bash
to do.– Dennis Williamson
5 hours ago