Splitting string ID code into various parts












1















I have a series of identification codes that I need to split out. The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].



An example of some codes includes S22-201, TT100-12, and V6-1B. Often there is no subdistrict, and all points fall within the same larger district (so no As or Cs or whatever at the end of the string.



I can do parts of it, like splitting at the hyphen.



!Original_ID!.split('-')[0]


and then extracting the district



!Split_ID![1:3]


But it seems like two steps for this are unnecessary, and only works when I know the specific number of characters in the string, which isn't realistic for a large data set.



I'd like to be able to grab each piece at once:




  • letters on the left of the hyphen

  • numbers on the left of the hyphen

  • numbers on the right of the hyphen

  • letters (if any) on the right of the hyphen.


I'd need the numeric fields to be integers (or I guess possibly floats in some rare cases maybe).










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    1















    I have a series of identification codes that I need to split out. The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].



    An example of some codes includes S22-201, TT100-12, and V6-1B. Often there is no subdistrict, and all points fall within the same larger district (so no As or Cs or whatever at the end of the string.



    I can do parts of it, like splitting at the hyphen.



    !Original_ID!.split('-')[0]


    and then extracting the district



    !Split_ID![1:3]


    But it seems like two steps for this are unnecessary, and only works when I know the specific number of characters in the string, which isn't realistic for a large data set.



    I'd like to be able to grab each piece at once:




    • letters on the left of the hyphen

    • numbers on the left of the hyphen

    • numbers on the right of the hyphen

    • letters (if any) on the right of the hyphen.


    I'd need the numeric fields to be integers (or I guess possibly floats in some rare cases maybe).










    share|improve this question









    New contributor




    vce500 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      1












      1








      1








      I have a series of identification codes that I need to split out. The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].



      An example of some codes includes S22-201, TT100-12, and V6-1B. Often there is no subdistrict, and all points fall within the same larger district (so no As or Cs or whatever at the end of the string.



      I can do parts of it, like splitting at the hyphen.



      !Original_ID!.split('-')[0]


      and then extracting the district



      !Split_ID![1:3]


      But it seems like two steps for this are unnecessary, and only works when I know the specific number of characters in the string, which isn't realistic for a large data set.



      I'd like to be able to grab each piece at once:




      • letters on the left of the hyphen

      • numbers on the left of the hyphen

      • numbers on the right of the hyphen

      • letters (if any) on the right of the hyphen.


      I'd need the numeric fields to be integers (or I guess possibly floats in some rare cases maybe).










      share|improve this question









      New contributor




      vce500 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I have a series of identification codes that I need to split out. The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].



      An example of some codes includes S22-201, TT100-12, and V6-1B. Often there is no subdistrict, and all points fall within the same larger district (so no As or Cs or whatever at the end of the string.



      I can do parts of it, like splitting at the hyphen.



      !Original_ID!.split('-')[0]


      and then extracting the district



      !Split_ID![1:3]


      But it seems like two steps for this are unnecessary, and only works when I know the specific number of characters in the string, which isn't realistic for a large data set.



      I'd like to be able to grab each piece at once:




      • letters on the left of the hyphen

      • numbers on the left of the hyphen

      • numbers on the right of the hyphen

      • letters (if any) on the right of the hyphen.


      I'd need the numeric fields to be integers (or I guess possibly floats in some rare cases maybe).







      python arcmap field-calculator






      share|improve this question









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      vce500 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question









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      share|improve this question








      edited 6 mins ago









      Taras

      2,2342727




      2,2342727






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      asked 5 hours ago









      vce500vce500

      62




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          2 Answers
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          2














          You're not going to be able to calculate two fields in one go.. though you can split it up into two calcs. I would do this with an update cursor:



          with arcpy.da.UpdateCursor(YourFeatureClass,['Original_ID','District','Split_ID']) as uCur:
          for sRow in uCur:
          OrigID = sRow[0].split('-')[0] # first element in the Original_ID
          charRng = range(len(OrigID)) # a range to iterate over
          Chars = ''
          Numbers = ''
          for Idx in charRng:
          if OrigID[Idx].isnumeric():
          Numbers += OrigID[Idx]
          else:
          chars += OrigID[Idx]
          sRow[1] = float(Numbers)
          sRow[2] = Chars
          uCur.updateRow(sRow)


          This shows how to break up a string into numbers and not numbers and put the values into a row, it should give you some ideas where to start from.






          share|improve this answer































            1














            Assuming you have four fields, region, district, place and subdistrict already added and you want to use the field calculator to populate them. You would have to run the calculator four times using an expression like:



            Code Block



            import re
            def parse(s):
            """The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].
            An example of a some codes include S22-201, TT100-12, and V6-1B.
            Often there is no subdistrict, and all points fall within the same larger district
            (so no As or Cs or whatever at the end of the string)."""

            letters = re.findall(r'[a-z A-Z]+', s)
            numbers = re.findall(r'[0-9]+', s)

            region = letters[0]
            district, place = [int(n) for n in numbers]
            try:
            subdistrict = letters[1]
            except IndexError:
            subdistrict = None

            return region, district, place, subdistrict


            Then for the region field, use:



            parse(!Original_ID!)[0]


            For district:



            parse(!Original_ID!)[1]


            For place:



            parse(!Original_ID!)[2]


            For subdistrict:



            parse(!Original_ID!)[3]


            However, I would use the update cursor approach suggested by Michael Stimson so you could update all four fields in one hit. Use the following in the python window of ArcMap/ArcGIS Pro:



            import re 
            def parse(s):
            etc... from code block above

            with arcpy.da.UpdateCursor(YourFeatureClass, ['Original_ID','Region', 'District', 'Place', 'Subdistrict']) as rows:
            for row in rows:
            region, district, place, subdistrict = parse(row[0])
            row = [row[0], region, district, place, subdistrict]
            rows.updateRow(row)





            share|improve this answer

























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              2 Answers
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              2 Answers
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              active

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              2














              You're not going to be able to calculate two fields in one go.. though you can split it up into two calcs. I would do this with an update cursor:



              with arcpy.da.UpdateCursor(YourFeatureClass,['Original_ID','District','Split_ID']) as uCur:
              for sRow in uCur:
              OrigID = sRow[0].split('-')[0] # first element in the Original_ID
              charRng = range(len(OrigID)) # a range to iterate over
              Chars = ''
              Numbers = ''
              for Idx in charRng:
              if OrigID[Idx].isnumeric():
              Numbers += OrigID[Idx]
              else:
              chars += OrigID[Idx]
              sRow[1] = float(Numbers)
              sRow[2] = Chars
              uCur.updateRow(sRow)


              This shows how to break up a string into numbers and not numbers and put the values into a row, it should give you some ideas where to start from.






              share|improve this answer




























                2














                You're not going to be able to calculate two fields in one go.. though you can split it up into two calcs. I would do this with an update cursor:



                with arcpy.da.UpdateCursor(YourFeatureClass,['Original_ID','District','Split_ID']) as uCur:
                for sRow in uCur:
                OrigID = sRow[0].split('-')[0] # first element in the Original_ID
                charRng = range(len(OrigID)) # a range to iterate over
                Chars = ''
                Numbers = ''
                for Idx in charRng:
                if OrigID[Idx].isnumeric():
                Numbers += OrigID[Idx]
                else:
                chars += OrigID[Idx]
                sRow[1] = float(Numbers)
                sRow[2] = Chars
                uCur.updateRow(sRow)


                This shows how to break up a string into numbers and not numbers and put the values into a row, it should give you some ideas where to start from.






                share|improve this answer


























                  2












                  2








                  2







                  You're not going to be able to calculate two fields in one go.. though you can split it up into two calcs. I would do this with an update cursor:



                  with arcpy.da.UpdateCursor(YourFeatureClass,['Original_ID','District','Split_ID']) as uCur:
                  for sRow in uCur:
                  OrigID = sRow[0].split('-')[0] # first element in the Original_ID
                  charRng = range(len(OrigID)) # a range to iterate over
                  Chars = ''
                  Numbers = ''
                  for Idx in charRng:
                  if OrigID[Idx].isnumeric():
                  Numbers += OrigID[Idx]
                  else:
                  chars += OrigID[Idx]
                  sRow[1] = float(Numbers)
                  sRow[2] = Chars
                  uCur.updateRow(sRow)


                  This shows how to break up a string into numbers and not numbers and put the values into a row, it should give you some ideas where to start from.






                  share|improve this answer













                  You're not going to be able to calculate two fields in one go.. though you can split it up into two calcs. I would do this with an update cursor:



                  with arcpy.da.UpdateCursor(YourFeatureClass,['Original_ID','District','Split_ID']) as uCur:
                  for sRow in uCur:
                  OrigID = sRow[0].split('-')[0] # first element in the Original_ID
                  charRng = range(len(OrigID)) # a range to iterate over
                  Chars = ''
                  Numbers = ''
                  for Idx in charRng:
                  if OrigID[Idx].isnumeric():
                  Numbers += OrigID[Idx]
                  else:
                  chars += OrigID[Idx]
                  sRow[1] = float(Numbers)
                  sRow[2] = Chars
                  uCur.updateRow(sRow)


                  This shows how to break up a string into numbers and not numbers and put the values into a row, it should give you some ideas where to start from.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 4 hours ago









                  Michael StimsonMichael Stimson

                  21.6k22360




                  21.6k22360

























                      1














                      Assuming you have four fields, region, district, place and subdistrict already added and you want to use the field calculator to populate them. You would have to run the calculator four times using an expression like:



                      Code Block



                      import re
                      def parse(s):
                      """The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].
                      An example of a some codes include S22-201, TT100-12, and V6-1B.
                      Often there is no subdistrict, and all points fall within the same larger district
                      (so no As or Cs or whatever at the end of the string)."""

                      letters = re.findall(r'[a-z A-Z]+', s)
                      numbers = re.findall(r'[0-9]+', s)

                      region = letters[0]
                      district, place = [int(n) for n in numbers]
                      try:
                      subdistrict = letters[1]
                      except IndexError:
                      subdistrict = None

                      return region, district, place, subdistrict


                      Then for the region field, use:



                      parse(!Original_ID!)[0]


                      For district:



                      parse(!Original_ID!)[1]


                      For place:



                      parse(!Original_ID!)[2]


                      For subdistrict:



                      parse(!Original_ID!)[3]


                      However, I would use the update cursor approach suggested by Michael Stimson so you could update all four fields in one hit. Use the following in the python window of ArcMap/ArcGIS Pro:



                      import re 
                      def parse(s):
                      etc... from code block above

                      with arcpy.da.UpdateCursor(YourFeatureClass, ['Original_ID','Region', 'District', 'Place', 'Subdistrict']) as rows:
                      for row in rows:
                      region, district, place, subdistrict = parse(row[0])
                      row = [row[0], region, district, place, subdistrict]
                      rows.updateRow(row)





                      share|improve this answer






























                        1














                        Assuming you have four fields, region, district, place and subdistrict already added and you want to use the field calculator to populate them. You would have to run the calculator four times using an expression like:



                        Code Block



                        import re
                        def parse(s):
                        """The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].
                        An example of a some codes include S22-201, TT100-12, and V6-1B.
                        Often there is no subdistrict, and all points fall within the same larger district
                        (so no As or Cs or whatever at the end of the string)."""

                        letters = re.findall(r'[a-z A-Z]+', s)
                        numbers = re.findall(r'[0-9]+', s)

                        region = letters[0]
                        district, place = [int(n) for n in numbers]
                        try:
                        subdistrict = letters[1]
                        except IndexError:
                        subdistrict = None

                        return region, district, place, subdistrict


                        Then for the region field, use:



                        parse(!Original_ID!)[0]


                        For district:



                        parse(!Original_ID!)[1]


                        For place:



                        parse(!Original_ID!)[2]


                        For subdistrict:



                        parse(!Original_ID!)[3]


                        However, I would use the update cursor approach suggested by Michael Stimson so you could update all four fields in one hit. Use the following in the python window of ArcMap/ArcGIS Pro:



                        import re 
                        def parse(s):
                        etc... from code block above

                        with arcpy.da.UpdateCursor(YourFeatureClass, ['Original_ID','Region', 'District', 'Place', 'Subdistrict']) as rows:
                        for row in rows:
                        region, district, place, subdistrict = parse(row[0])
                        row = [row[0], region, district, place, subdistrict]
                        rows.updateRow(row)





                        share|improve this answer




























                          1












                          1








                          1







                          Assuming you have four fields, region, district, place and subdistrict already added and you want to use the field calculator to populate them. You would have to run the calculator four times using an expression like:



                          Code Block



                          import re
                          def parse(s):
                          """The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].
                          An example of a some codes include S22-201, TT100-12, and V6-1B.
                          Often there is no subdistrict, and all points fall within the same larger district
                          (so no As or Cs or whatever at the end of the string)."""

                          letters = re.findall(r'[a-z A-Z]+', s)
                          numbers = re.findall(r'[0-9]+', s)

                          region = letters[0]
                          district, place = [int(n) for n in numbers]
                          try:
                          subdistrict = letters[1]
                          except IndexError:
                          subdistrict = None

                          return region, district, place, subdistrict


                          Then for the region field, use:



                          parse(!Original_ID!)[0]


                          For district:



                          parse(!Original_ID!)[1]


                          For place:



                          parse(!Original_ID!)[2]


                          For subdistrict:



                          parse(!Original_ID!)[3]


                          However, I would use the update cursor approach suggested by Michael Stimson so you could update all four fields in one hit. Use the following in the python window of ArcMap/ArcGIS Pro:



                          import re 
                          def parse(s):
                          etc... from code block above

                          with arcpy.da.UpdateCursor(YourFeatureClass, ['Original_ID','Region', 'District', 'Place', 'Subdistrict']) as rows:
                          for row in rows:
                          region, district, place, subdistrict = parse(row[0])
                          row = [row[0], region, district, place, subdistrict]
                          rows.updateRow(row)





                          share|improve this answer















                          Assuming you have four fields, region, district, place and subdistrict already added and you want to use the field calculator to populate them. You would have to run the calculator four times using an expression like:



                          Code Block



                          import re
                          def parse(s):
                          """The format of these codes is [region(letter)][district(number)] - [place(number)][subdistrict(letter)].
                          An example of a some codes include S22-201, TT100-12, and V6-1B.
                          Often there is no subdistrict, and all points fall within the same larger district
                          (so no As or Cs or whatever at the end of the string)."""

                          letters = re.findall(r'[a-z A-Z]+', s)
                          numbers = re.findall(r'[0-9]+', s)

                          region = letters[0]
                          district, place = [int(n) for n in numbers]
                          try:
                          subdistrict = letters[1]
                          except IndexError:
                          subdistrict = None

                          return region, district, place, subdistrict


                          Then for the region field, use:



                          parse(!Original_ID!)[0]


                          For district:



                          parse(!Original_ID!)[1]


                          For place:



                          parse(!Original_ID!)[2]


                          For subdistrict:



                          parse(!Original_ID!)[3]


                          However, I would use the update cursor approach suggested by Michael Stimson so you could update all four fields in one hit. Use the following in the python window of ArcMap/ArcGIS Pro:



                          import re 
                          def parse(s):
                          etc... from code block above

                          with arcpy.da.UpdateCursor(YourFeatureClass, ['Original_ID','Region', 'District', 'Place', 'Subdistrict']) as rows:
                          for row in rows:
                          region, district, place, subdistrict = parse(row[0])
                          row = [row[0], region, district, place, subdistrict]
                          rows.updateRow(row)






                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited 2 hours ago

























                          answered 2 hours ago









                          user2856user2856

                          30.3k258105




                          30.3k258105






















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