Ngtjyty

How to draw the letter π not in the standard way (i.e. pi)?

I mean "draw", not "type"! Today there will be no pi, but there will be something like this

documentclass[tikz]{standalone}

begin{document}

begin{tikzpicture}

draw (0,2)--(3,2);

draw (1,0)--(1,2);

draw (2,0)--(2,2);

end{tikzpicture}

end{document}

(inspired by David Carlisle – I draw this in TikZ just because I don't know how to use picture ;))

Or this

documentclass[tikz]{standalone}

usepackage{tikzducks}

begin{document}

begin{tikzpicture}

duck

duck[xshift=1cm,yshift=2cm]

duck[xshift=1cm,yshift=4cm]

duck[xshift=1cm,yshift=6cm]

duck[xshift=0cm,yshift=8cm]

duck[xshift=-2cm,yshift=7.5cm]

duck[xshift=2cm,yshift=8cm]

duck[xshift=4cm,yshift=8cm]

duck[xshift=6cm,yshift=8cm]

duck[xshift=8cm,yshift=8cm]

duck[xshift=5cm,yshift=6cm]

duck[xshift=5cm,yshift=4cm]

duck[xshift=5.5cm,yshift=2cm]

duck[xshift=6.5cm,yshift=0cm]

duck[xshift=8cm,yshift=1cm]

node[font=huge] at (4,11) {Happy $pi$ day with verb|tikzducks|!};

end{tikzpicture}

end{document}

They are my proudest π drawings, and as today is Pi day, I'd like to see yours!

Writing π with the digits of π - using the verbatim environment.

documentclass{article}

linespread{0.7}

begin{document}

begin{verbatim}

     3.141592653589793238462643383279

   5028841971693993751058209749445923

  07816406286208998628034825342117067

  9821    48086         5132     

 823      06647        09384

46        09550        58223

17        25359        4081

          2848         1117

          4502         8410

          2701         9385

         21105        55964

         46229        48954

         9303         81964

         4288         10975

        66593         34461

       284756         48233

       78678          31652        71

      2019091         456485       66

     9234603           48610454326648

    2133936            0726024914127

    3724587             00660631558

    817488               152092096

end{verbatim}

end{document}

Based on ascii art drawing by Jorel - https://www.flickr.com/photos/jorel314/3352784321/

Happy pi(less) day!!

documentclass{report}

begin{document}

noindent%

rule{30pt}{1pt}\[-1pt]

rule{8pt}{0pt}%

rule{1pt}{30pt}%

rule{12pt}{0pt}%

rule{1pt}{30pt}

end{document}

One should also honor Euler a bit.

documentclass[tikz,border=3.14mm]{standalone}

usepackage{tikzlings,amsmath}

makeatletter

tikzset{/thing/.cd,

 pie/.code=thing@cheesetruedefthing@cheese{#1}, %<-pretend you didn't see that

 pie/.default=pink!70!red}

makeatother                            

begin{document}

begin{tikzpicture}[font=sffamily]

marmot[pie,whiskers,teeth,shadow]

node[anchor=east,scale=5,transform shape] at (-0.6,1) {$picdotmathsf{e}=text{sffamily pie}$};

end{tikzpicture}

end{document}

We could extract the MetaPost paths for the glyph pi from the font and draw it using LuaTeX. This does not yet work with TeX Live 2019. Something in luamplib and ConTeXt has changed.

documentclass{article}



usepackage{fontspec}

setmainfont{latinmodern-math.otf}



usepackage{luacode}

begin{luacode*}

-- We need some utilities from ConTeXt

callbacks = callbacks or {}

callbacks.supported = callbacks.supported or {}

dofile(kpse.find_file("util-fmt.lua"))

dofile(kpse.find_file("node-ini.lua"))

dofile(kpse.find_file("font-mps.lua"))

dofile(kpse.find_file("font-shp.lua"))



-- That's a simple reimplemetation of ConTeXt's showshape macro

function outlinepaths(character)

    local fontid      = font.current()

    local shapedata   = fonts.hashes.shapes[fontid] -- by index

    local chardata    = fonts.hashes.characters[fontid] -- by unicode

    local shapeglyphs = shapedata.glyphs or { }



    character = utf.byte(character)

    local c = chardata[character]

    if c then

        if not c.index then

            return {}

        end

        local glyph = shapeglyphs[c.index]

        if glyph and (glyph.segments or glyph.sequence) then

            local units  = shapedata.units or 1000

            local factor = 100/units

            local paths  = fonts.metapost.paths(glyph,factor)

            return paths

        end

    end

end

end{luacode*}



usepackage{luamplib}

mplibsetformat{metafun}

everymplib{beginfig(0);}

everyendmplib{endfig;}



defmpdefineoutlines#1{directlua{

    local char = "luaescapestring{#1}"

    local outlines = outlinepaths("#1")

    for i, path in ipairs(outlines) do

        tex.print("fill " .. path .. ";")

    end

  }}



begin{document} 



begin{mplibcode}



  mpdefineoutlines{𝜋}



end{mplibcode}



end{document}

Instead of using luamplib, we could also simply print the path to the log file and copy it to a MetaPost file. With some additonal formatting we get:

prologues := 3;

outputformat := "pdf";



beginfig(1)

  fill (56.70,40.70)

    .. controls (56.70,43.10) and (54.60,43.10)

    .. (52.70,43.10)

    -- (19.20,43.10)

    .. controls (17,43.10) and (13.20,43.10)

    .. (8.80,38.40)

    .. controls (5.30,34.50) and (2.70,29.90)

    .. (2.70,29.40)

    .. controls (2.70,29.40) and (2.70,28.40)

    .. (3.90,28.40)

    .. controls (4.70,28.40) and (4.90,28.80)

    .. (5.50,29.60)

    .. controls (10.40,37.30) and (16.20,37.30)

    .. (18.20,37.30)

    -- (23.90,37.30)

    .. controls (20.70,25.20) and (15.30,13.10)

    .. (11.10,4)

    .. controls (10.30,2.50) and (10.30,2.30)

    .. (10.30,1.60)

    .. controls (10.30,-0.30) and (11.90,-1.10)

    .. (13.20,-1.10)

    .. controls (16.20,-1.10) and (17,1.70)

    .. (18.20,5.40)

    .. controls (19.60,10) and (19.60,10.20)

    .. (20.90,15.20)

    -- (26.50,37.30)

    -- (37.80,37.30)

    .. controls (34.50,22.50) and (33.60,18.20)

    .. (33.60,11.50)

    .. controls (33.60,10) and (33.60,7.30)

    .. (34.40,3.90)

    .. controls (35.40,-0.50) and (36.50,-1.10)

    .. (38,-1.10)

    .. controls (40,-1.10) and (42.10,0.70)

    .. (42.10,2.70)

    .. controls (42.10,3.30) and (42.10,3.50)

    .. (41.50,4.90)

    .. controls (38.60,12.10) and (38.60,18.60)

    .. (38.60,21.40)

    .. controls (38.60,26.70) and (39.30,32.10)

    .. (40.40,37.30)

    -- (51.80,37.30)

    .. controls (53.10,37.30) and (56.70,37.30)

    .. (56.70,40.70)

    -- cycle;

endfig;

end

Or you can even use the path with TikZ.

documentclass{article}



usepackage{tikz}



begin{document} 



begin{tikzpicture}[x=1pt,y=1pt]



  fill (56.70,40.70)

    .. controls (56.70,43.10) and (54.60,43.10)

    .. (52.70,43.10)

    -- (19.20,43.10)

    .. controls (17,43.10) and (13.20,43.10)

    .. (8.80,38.40)

    .. controls (5.30,34.50) and (2.70,29.90)

    .. (2.70,29.40)

    .. controls (2.70,29.40) and (2.70,28.40)

    .. (3.90,28.40)

    .. controls (4.70,28.40) and (4.90,28.80)

    .. (5.50,29.60)

    .. controls (10.40,37.30) and (16.20,37.30)

    .. (18.20,37.30)

    -- (23.90,37.30)

    .. controls (20.70,25.20) and (15.30,13.10)

    .. (11.10,4)

    .. controls (10.30,2.50) and (10.30,2.30)

    .. (10.30,1.60)

    .. controls (10.30,-0.30) and (11.90,-1.10)

    .. (13.20,-1.10)

    .. controls (16.20,-1.10) and (17,1.70)

    .. (18.20,5.40)

    .. controls (19.60,10) and (19.60,10.20)

    .. (20.90,15.20)

    -- (26.50,37.30)

    -- (37.80,37.30)

    .. controls (34.50,22.50) and (33.60,18.20)

    .. (33.60,11.50)

    .. controls (33.60,10) and (33.60,7.30)

    .. (34.40,3.90)

    .. controls (35.40,-0.50) and (36.50,-1.10)

    .. (38,-1.10)

    .. controls (40,-1.10) and (42.10,0.70)

    .. (42.10,2.70)

    .. controls (42.10,3.30) and (42.10,3.50)

    .. (41.50,4.90)

    .. controls (38.60,12.10) and (38.60,18.60)

    .. (38.60,21.40)

    .. controls (38.60,26.70) and (39.30,32.10)

    .. (40.40,37.30)

    -- (51.80,37.30)

    .. controls (53.10,37.30) and (56.70,37.30)

    .. (56.70,40.70)

    -- cycle;



end{tikzpicture}



end{document}

The output is rather unspectacular.